A) 0.14
B) 1.4
C) 1
D) 1.4
Correct Answer: D
Solution :
\[\frac{{{(6.25)}^{\frac{1}{2}}}\times {{(0.0144)}^{\frac{1}{2}}}+1}{{{(0.027)}^{\frac{1}{3}}}\times {{(81)}^{\frac{1}{4}}}}\] \[=\frac{2.5\times 0.12+1}{0.3\times 3}=\frac{0.3+1}{0.9}=\frac{1.3}{0.9}=1.4444=1.\bar{4}\]You need to login to perform this action.
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