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SSC Sample Paper Mock Test-3 SSC CGL Tear-II Paper-1

  • question_answer
    If \[(A-B)=\frac{\pi }{3},\]then the value of \[cos\text{ }A\text{ }cos\text{ }B+sin\text{ }A\text{ }sin\text{ }B\]is

    A)  \[\frac{1}{2}\] 

    B)  \[1\]

    C)  \[\frac{1}{3}\]                         

    D)  \[\frac{3}{2}\]

    Correct Answer: A

    Solution :

    As, \[\cos A\cos B+\sin A\sin B=\cos (A-B)\] \[=\cos \left( \frac{\pi }{3} \right)=\frac{1}{2}\left( \therefore A-B=\frac{\pi }{3} \right)\]                        


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