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SSC Sample Paper Mock Test-3 SSC CGL Tear-II Paper-1

  • question_answer
    The value of \[3\sin 15{}^\circ -4{{\sin }^{3}}15{}^\circ \]is.

    A)  1                                

    B)  \[\frac{1}{2}\]

    C)  \[\frac{1}{\sqrt{2}}\]    

    D)  \[0\]

    Correct Answer: C

    Solution :

    As, \[3\sin \theta -4{{\sin }^{3}}\theta =\sin 3\theta \] So, \[3\sin 15{}^\circ -4{{\sin }^{3}}15{}^\circ =\sin 3\,\,(15){}^\circ =\sin 45{}^\circ =\frac{1}{\sqrt{2}}\]                        


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