A) Right triangle
B) Isosceles triangle
C) Scalene triangle
D) Equilateral triangle
Correct Answer: B
Solution :
Let \[A\,\,(-\,\,4,0),\]\[B\,\,(4,0)\]and \[C\,\,(0,3).\] \[AB=\sqrt{[{{(4-(-\,\,4)]}^{2}}+{{(0-0)}^{2}}}\] \[=\sqrt{{{(4+4)}^{2}}}\Rightarrow \sqrt{{{8}^{2}}}=8\] \[BC=\sqrt{{{(0-4)}^{2}}+{{(3-0)}^{2}}}\] \[=\sqrt{16+9}=\sqrt{25}=5\] \[AC=\sqrt{[{{(0-(-\,\,4)]}^{2}}+{{(3-0)}^{2}}}\] \[=\sqrt{16+9}=\sqrt{25}=5\] \[\therefore \]BC = AC \[\therefore \]\[\Delta ABC\] is an isosceles triangle.
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