A) 41 m/s and 39 m/s
B) 32 m/s and 43 m/s
C) 42 m/s and 38 m/s
D) None of these
Correct Answer: C
Solution :
Let \[{{v}_{1}}\]be the velocity of fast train and Vg be the velocity of slower train. \[\therefore \] \[\frac{110+130}{{{v}_{1}}-{{v}_{2}}}=60\] \[\Rightarrow \] \[{{v}_{1}}-{{v}_{2}}=4\] ?(i) Again,\[\frac{110+130}{{{v}_{1}}+{{v}_{2}}}=3\]\[\Rightarrow \]\[{{v}_{1}}+{{v}_{2}}=80\] On adding Eqs. (i) and (ii), we get \[2{{v}_{1}}=84\] \[\Rightarrow \] \[{{v}_{1}}=42\,\,m/s\] and put the value of\[{{v}_{1}}\] in Eq. (ii), we get \[{{v}_{2}}=38\,\,m/s.\]You need to login to perform this action.
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