A) \[133\frac{1}{3}\]
B) \[\frac{1}{200}\]
C) 72
D) 66
Correct Answer: A
Solution :
Weight of \[=200\times \frac{5}{8}=125\,\,g\] Weight of copper \[=200\times \frac{3}{8}=75\,\,g\] Let the ratio of 125 g zinc and x gram copper be 3 : 5 \[\therefore \] \[\frac{125}{x}=\frac{3}{5}\] \[\therefore \] \[x=\frac{125\times 5}{3}=\frac{625}{3}\,\,g\] \[\therefore \]Addition of copper in mixture \[=\frac{625}{3}-75=\frac{625-225}{3}=\frac{400}{3}=133\frac{1}{3}\,\,g\]You need to login to perform this action.
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