A) 10
B) 15
C) 20
D) 25
Correct Answer: B
Solution :
Let the numbers are x and y, According to the question, \[\frac{x}{y}=\frac{2}{3}\] \[x=\frac{2y}{3}\] ?(i) Again, \[\frac{x+3}{y+3}=\frac{3}{4}\] \[4x+12=3y+9\] ?(ii) Putting the value of x in Eq. (ii), we get \[4\times \frac{2y}{3}+12=3y+9\] \[\Rightarrow \] \[3y-\frac{8y}{3}=12-9\] \[\Rightarrow \] \[\frac{9y-8y}{3}=3\] \[\Rightarrow \] \[y=3\times 3=9\] \[\therefore \] \[x=\frac{2y}{3}=\frac{2\times 9}{3}=6\] \[\therefore \] Sum of the numbers\[=9+6=15\]You need to login to perform this action.
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