A) 966
B) 696
C) 669
D) 666
Correct Answer: B
Solution :
Let the number be 29x and 29 y respectively where x and y are prime to each other. \[\therefore \] LCM of 29x and y = 29xy Now, 29xy = 4147 \[\therefore \] \[xy=\frac{4147}{29}=143\] Thus \[xy=11\times 13\] Numbers are \[29\times 11=319\]and \[29\times 13=377\] \[\therefore \]Required sum \[=377+319=696\]You need to login to perform this action.
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