A) \[\pi /3\]
B) \[\pi /4\]
C) \[\pi /6\]
D) \[\pi /2\]
Correct Answer: B
Solution :
\[\cos \theta +\sin \theta =\sqrt{2}\] \[\frac{\cos \theta }{\sqrt{2}}+\frac{\sin \theta }{\sqrt{2}}=1\] (\[\because \]divided throughout by \[\sqrt{2}\]) \[\Rightarrow \]\[\cos \theta \cos 45{}^\circ +\sin \theta 45{}^\circ =1\] \[\cos (\theta -45{}^\circ )=1=cos0\] \[\therefore \] \[\theta -45{}^\circ =0\] \[\Rightarrow \] \[\theta =45{}^\circ =\pi /4\]
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