question_answer

The least multiple of 13, which on dividing by 5, 6, 7 and 8 leaves remainder 2 in each case is

A)  2520               

B)  842

C)  2522

D)  840

Correct Answer: C

Solution :

LCM of 4, 5, 6, 7 and 8 \[=2\times 2\times 2\times 3\times 5\times 7=840\] Let required number be 840 K + 2 which is multiple of 13. Least value of K for which (840 K + 2) is divisible be 13 is K = 3 \[\therefore \]Required number \[=840\times 3+2=2520+2=2522\]