A) \[2\sqrt{38}\,\,m\]
B) \[4\sqrt{38}\,\,cm\]
C) \[2\sqrt{19}\,\,m\]
D) \[19\,\,m\]
Correct Answer: A
Solution :
The length of the longest rod = The diagonal of the hall \[=\sqrt{{{10}^{2}}+{{6}^{2}}+{{4}^{2}}}=\sqrt{100+36+16}=\sqrt{152}\] \[=\sqrt{2\times 2\times 38}=2\sqrt{38}\,\,\text{m}\]You need to login to perform this action.
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