A) 8 h
B) 7 b
C) \[4\frac{1}{3}\]h
D) 14 b
Correct Answer: D
Solution :
Work done in 1 h by the filling pump\[=\frac{1}{2}\] Work done in 1 h by the leak and the filling pump \[=\frac{3}{7}\] \[\therefore \] Work done by the leak in 1 h \[=\frac{1}{2}-\frac{3}{7}=\frac{7-6}{14}=\frac{1}{14}\] Hence, the leak can empty the tank in 14 h.You need to login to perform this action.
You will be redirected in
3 sec