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SSC Sample Paper Mock Test-4 SSC CGL Tear-II Paper-1

  • question_answer
         If\[x=1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}}\]then, the value of\[2x+\frac{7}{4}\]is

    A)  3                                

    B)  4

    C)  5        

    D)  6

    Correct Answer: C

    Solution :

    \[x=1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}=1+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{3}{2}}}}\] \[=1+\frac{1}{1+\frac{1}{1+\frac{2}{3}}}=1+\frac{1}{1+\frac{1}{\frac{5}{3}}}=1+\frac{1}{1+\frac{3}{5}}\] \[=1+\frac{1}{\frac{8}{5}}=1+\frac{5}{8}=\frac{13}{8}\] \[\therefore \]\[2x+\frac{7}{4}=2\times \frac{13}{8}+\frac{7}{4}\] \[=\frac{13+7}{4}=\frac{20}{4}=5\]                        


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