A) 16 : 9
B) 9 : 16
C) 9 : 12
D) 16 : 12
Correct Answer: A
Solution :
Let, the height and base of first triangle be \[{{h}_{1}}\] and respectively and that of second triangle \[{{h}_{2}}\] and respectively Now,\[\frac{\text{Area}\,\,\text{of}\,\,\text{first}\,\,\text{triangle}}{\text{Area}\,\,\text{of}\,\text{second}\,\,\text{triangle}}=\frac{4}{3}\] \[\Rightarrow \]\[\frac{\frac{1}{2}{{b}_{1}}{{h}_{1}}}{\frac{1}{2}{{b}_{2}}{{h}_{2}}}=\frac{4}{3}\]\[\Rightarrow \]\[\frac{{{b}_{1}}}{{{b}_{2}}}\times \frac{3}{4}=\frac{4}{3}\] \[\Rightarrow \]\[\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{4\times 4}{3\times 3}=\frac{16}{9}\]
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