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SSC Sample Paper Mock Test-4 SSC CGL Tear-II Paper-1

  • question_answer
    If \[A=\frac{x+1}{x-1}\]and\[B=\frac{x-1}{x+1},\]then A+B is

    A)  \[\frac{2\,\,({{x}^{2}}-1)}{({{x}^{2}}+1)}\]             

    B)  \[\frac{2\,\,({{x}^{2}}+1)}{{{(x-1)}^{2}}}\]

    C)  \[\frac{2\,\,({{x}^{2}}+1)}{{{x}^{2}}-1}\]   

    D)  None of these

    Correct Answer: C

    Solution :

    \[A+B=\frac{x+1}{x-1}+\frac{x-1}{x+1}=\frac{{{(x+1)}^{2}}+{{(x-1)}^{2}}}{(x-1)(x+1)}\] \[=\frac{{{x}^{2}}+2x+1+{{x}^{2}}-2x+1}{{{x}^{2}}-1}=\frac{2\,\,({{x}^{2}}+1)}{{{x}^{2}}-1}\]     


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