A) \[15{}^\circ \]
B) \[40{}^\circ \]
C) \[45{}^\circ \]
D) None of these
Correct Answer: B
Solution :
Through the point E, draw GEH ||AB || CD. AB| | GE and BE is the transversal. \[\therefore \] \[\angle ABE+\angle GEB=180{}^\circ \] \[\Rightarrow \] \[120{}^\circ +\angle GEB=180{}^\circ \] \[\therefore \] \[\angle GEB=60{}^\circ \] Again, CD| | EH and CE is the transversal. \[\therefore \] \[\angle DCE+\angle CEH=180{}^\circ \] \[\Rightarrow \] \[\angle CEH=180{}^\circ \] Now, \[\angle GEB+\angle BEC+\angle CEH=180{}^\circ \] \[\Rightarrow \] \[60{}^\circ +x+80{}^\circ =180{}^\circ \] \[\Rightarrow \] \[x=40{}^\circ \]You need to login to perform this action.
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