A) 54, 162
B) 108, 108
C) 27, 189
D) 55, 127
Correct Answer: C
Solution :
Let the numbers be 27a and 27b \[27a+27b=216\]\[\Rightarrow \]\[a+b=\frac{216}{27}\]\[\therefore \]\[a+b=8\] Co-primes with sum 8 are (1, 7) and (3, 5) So, the numbers are \[(27\times 1)\,\,(27\times 7)\] or\[(27\times 3)\,\,(27\times 5)\] i.e., (27 and 189) or (81 and 135)You need to login to perform this action.
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