A) 0
B) \[\frac{1}{2}\]
C) 1
D) 2
Correct Answer: C
Solution :
\[a+\frac{1}{b}=1\]\[\Rightarrow \]\[a=\left( 1-\frac{1}{b} \right)\]\[\Rightarrow \]\[a=\left( \frac{b-1}{b} \right)\]\[\Rightarrow \]\[\frac{1}{a}=\frac{b}{b-1}\] \[b+\frac{1}{c}=2\]\[\Rightarrow \]\[\frac{1}{c}=1-b=c=\frac{1}{1-b}\] \[c+\frac{1}{b}=\frac{1}{(1-b)}+\frac{b}{(b-1)}=\frac{1}{(1-b)}-\frac{b}{(1-b)}=\left( \frac{1-b}{1-b} \right)=1\]You need to login to perform this action.
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