A) Decrease approximately by 20%
B) Increase approximately by 2%
C) Increase approximately by 20%
D) Decrease approximately by 2%
Correct Answer: D
Solution :
Suppose strength of school in 1997 =100 |
Strength in 1998 after 10% increase |
\[=100\times \frac{100+10}{100}=110\] |
In 1999, 10% decrease \[=110\times \frac{100-10}{100}=99\] |
In 2000, 10% increase \[=99\times \frac{100+10}{100}=108.9\] |
In 2001, 10% decrease |
\[=108.9\times \frac{100-10}{100}=98.01\] |
Per cent decrease \[=100-98.01\] |
\[=\frac{1.99}{100}\times 100\] |
\[=1.99%\approx 2%\] |
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