A) AE
B) OB
C) \[\frac{1}{3}\]AE
D) \[\frac{1}{3}\]FC
Correct Answer: A
Solution :
As E is the centroid of \[\Delta ABD\]and AO is one of its medians \[\Rightarrow \] \[AE:EO=2:1\] \[\therefore \] \[EO=\frac{1}{3}OA\] Similarly, \[FO=\frac{1}{3}OC\] \[\therefore \] \[EO+OF=\frac{1}{3}OA+\frac{1}{3}OC\] \[=\frac{1}{3}AC=AE\] \[\therefore \] \[EF=AE\]You need to login to perform this action.
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