A) \[\frac{200}{\sqrt{3}-1}\,\,m\]
B) \[\frac{200}{\sqrt{3}+1}\,\,m\]
C) \[\frac{100}{\sqrt{3}-1}\,\,m\]
D) \[\frac{100}{\sqrt{3}+1}\,\,m\]
Correct Answer: A
Solution :
Here, Applying shortcut method |
Here, \[x=200\,\,\text{m},\]\[{{\theta }_{1}}=45{}^\circ ,\]\[{{\theta }_{2}}=30{}^\circ \] |
\[h=\frac{x}{\cot {{\theta }_{2}}-\cot {{\theta }_{1}}}\] |
\[=\frac{200}{\cot 30{}^\circ -\cot 45{}^\circ }\] |
\[=\frac{200}{\sqrt{3}-1}\] |
So, height of tower, |
\[h=\frac{200}{\sqrt{3}-1}\text{m}\] |
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