Directions: Read the following table and answer the questions given below. | ||||||||||||||||||||||||
|
A) 15
B) 20
C) 10
D) 5
Correct Answer: D
Solution :
Private internet users in 1998-99 =12000 Total internet users \[=230000+12000=242000\] Required percentage \[=\frac{12000}{242000}\times 100\] = 4.96%\[\approx \] 5% (approx.)You need to login to perform this action.
You will be redirected in
3 sec