A) \[\frac{25}{4}\]
B) 4
C) 9
D) 16
Correct Answer: B
Solution :
\[{{5}^{\sqrt{x}}}+{{12}^{\sqrt{x}}}={{13}^{\sqrt{x}}}\] we know that \[{{5}^{2}}+{{12}^{2}}={{13}^{2}}\] \[\Rightarrow \] \[\sqrt{x}=2\] \[\therefore \] \[x={{2}^{2}}=4\]You need to login to perform this action.
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