A) \[16\frac{2}{3}\,\,\text{s}\]
B) 18 s
C) 20 s
D) 22 s
Correct Answer: C
Solution :
Let the length of the train = x m |
When a train crosses a platform, the distance covered |
= Length of (Train \[+\] Platform) |
According to the question, |
Speed of train \[=\frac{x}{10}=\frac{x+300}{25}\] |
\[\Rightarrow \] \[25x=10x+3000\] |
\[\Rightarrow \] \[15x=3000\] |
\[\Rightarrow \] \[x=\frac{3000}{15}=200\,\,m\] |
\[\therefore \] Length of train \[=200\,\,m\] |
Speed of train \[=\frac{x}{10}=\frac{200}{10}=20\,\,m/s\] |
\[\therefore \] Time taken in crossing a 200 m long platform |
\[=\frac{200+200}{20}=20\,\,s\] |
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