A) 162
B) 108
C) 96
D) 54
Correct Answer: A
Solution :
Let the original number of students be 2x, 3x and 4x in three classes. |
According to the question, |
\[\frac{2x+12}{3x+12}=\frac{8}{11}\] |
\[\Rightarrow \] \[24x+96=22x+132\] |
\[\Rightarrow \] \[2x=132-96=36\] |
\[\Rightarrow \] \[x=\frac{36}{2}=18\] |
\[\therefore \] Original number of students |
\[=2x+3x+4x\] |
\[9x=9\times 18=162\] |
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