A) 70
B) 75
C) 73
D) 71
Correct Answer: C
Solution :
Total number of Seats (Ex. class) |
\[=500\times \frac{10}{100}=50\] |
\[\therefore \] Total number of seats (Chaircar) |
\[=500-50=450\] |
\[\therefore \] Total number of booked seats |
\[=500\times \frac{85}{100}=425\] |
\[\therefore \] Total number of booked seats (Ex. class) |
\[=50\times \frac{96}{100}=48\] |
\[\therefore \]Total number of empty seats (Chaircar) |
\[=450-(425-48)=73\] |
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