A) \[110{}^\circ \]
B) \[120{}^\circ \]
C) \[125{}^\circ \]
D) \[130{}^\circ \]
Correct Answer: A
Solution :
\[\angle HEB=180{}^\circ -60{}^\circ -50{}^\circ =70{}^\circ \] Since HF || BE and HE is transversal line \[\therefore \] \[\angle FHE+\angle HEB=180{}^\circ \](interior angle) \[\Rightarrow \] \[\angle FHE+70{}^\circ =180{}^\circ \] \[\therefore \] \[\angle FHE=110{}^\circ \]You need to login to perform this action.
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