A) \[2a\]
B) \[0\]
C) \[2b\]
D) \[b-c\]
Correct Answer: B
Solution :
\[\frac{a}{(a-b)(a-c)}+\frac{b}{(b-c)(b-a)}+\frac{c}{(c-a)(c-b)}\] |
\[=\frac{-\,\,a}{(a-b)(c-a)}-\frac{b}{(b-c)(a-b)}-\frac{c}{(c-a)(b-c)}\] |
\[=\frac{(-\,\,a)(b-c)-b(c-a)-c(a-b)}{(a-b)(b-c)(c-a)}\] |
\[=\frac{-ab+ac-bc+ab-ac+bc}{(a-b)(b-c)(c-a)}\] |
\[=\frac{0}{(a-b)(b-c)(c-a)}=0\] |
You need to login to perform this action.
You will be redirected in
3 sec