A) \[\frac{a-1}{a+1}\]
B) \[\frac{1}{{{a}^{2}}+a+1}\]
C) \[1\]
D) \[\frac{{{(a+1)}^{2}}}{(a-1)}\]
Correct Answer: D
Solution :
\[R\div S=\frac{{{a}^{3}}+1}{a-1}+\frac{{{a}^{2}}-a+1}{a+1}=\frac{{{a}^{3}}+1}{a-1}\times \frac{a+1}{({{a}^{2}}-a+1)}\] \[=\frac{(a+1)({{a}^{2}}-a+1)(a+1)}{(a-1)({{a}^{2}}-a+1)}=\frac{{{(a+1)}^{2}}}{(a-1)}\]You need to login to perform this action.
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