A) 0
B) 1
C) 10
D) 30
Correct Answer: C
Solution :
Let \[1.5=a,\]\[4.7=b,\]\[3.8=c\] \[\therefore \]Expression \[=\frac{{{a}^{3}}+{{b}^{3}}+{{c}^{3}}\,\,3abc}{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}-ab-bc-ca}\] \[=a+b+c=1.5+4.7+3.8=10\]You need to login to perform this action.
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