A) \[70{}^\circ \]
B) \[105{}^\circ \]
C) \[120{}^\circ \]
D) \[130{}^\circ \]
Correct Answer: D
Solution :
Draw FEG || AB || CD AB ||EG and AE is the transversal \[\therefore \]\[\angle BAE+\angle AEG=180{}^\circ \Rightarrow 110{}^\circ +\angle AEG=180{}^\circ \] \[\angle AEG=70{}^\circ \] Again, EG||CD and EC is the transversal \[\therefore \] \[\angle GEC+\angle ECD=180{}^\circ \] \[\Rightarrow \] \[\angle GEC+120{}^\circ \]\[\Rightarrow \]\[180{}^\circ \] \[\Rightarrow \] \[\angle GEC=60{}^\circ \] \[\therefore \] \[x=70{}^\circ +60{}^\circ =130{}^\circ \]You need to login to perform this action.
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