A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: D
Solution :
In \[\Delta APS\]and \[\Delta PBQ,\] (Given) PB = AS AP = BQ \[\therefore \]\[\Delta APS\]and \[\Delta PBQ\]are congruent, \[\therefore \] SP = PQ \[\angle SPA=\angle BQP\] and \[\angle ASP=\angle BPQ\] \[\therefore \] \[\angle SPQ=90{}^\circ \]You need to login to perform this action.
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