A) \[-\,\,3\]
B) 0
C) 1
D) 3
Correct Answer: D
Solution :
Given \[a+b+c=0\] \[\Rightarrow \] \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}=3abc\] \[\Rightarrow \] \[\frac{{{a}^{3}}}{abc}+\frac{{{b}^{3}}}{abc}+\frac{{{c}^{3}}}{abc}=3\] \[\Rightarrow \]\[\frac{{{a}^{2}}}{bc}+\frac{{{b}^{2}}}{ac}+\frac{{{c}^{2}}}{ab}=3\]You need to login to perform this action.
You will be redirected in
3 sec