A) A = 3S
B) A = 2S
C) A = S
D) A < S
Correct Answer: C
Solution :
Let side of square \[=x\] \[\therefore \] Radius of sphere \[=x\] Surface area of sphere, \[A=4\pi {{x}^{2}}\] Since, square revolves round a side to generate a cylinder whose height and radius are x and x. respectively. \[\therefore \] \[S=2\pi \times (x+x)=4\pi {{x}^{2}}\] \[\therefore \] It is clear that A = SYou need to login to perform this action.
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