SSC Sample Paper Mock Test-7 SSC CGL Tear-II Paper-1

  • question_answer
    A and B can do a piece of work in 12 days, B and C in 8 days and C and A in 6 days. How long would B take to do the same work alone?

    A)  24 days

    B)  32 days

    C)  40 days

    D)  48 days

    Correct Answer: D

    Solution :

    (A + B)'s 1 day's work\[=\frac{1}{2}\]                 ?(i)
    (B + C)'s 1 day's work \[=\frac{1}{8}\]                ?(ii)
    (C + A)'s 1 day's work \[=\frac{1}{6}\]                ?(iii)    
    On adding, 2 (A + B + C)'s 1 day's work
    \[=\frac{1}{12}+\frac{1}{8}+\frac{1}{6}\]
    \[=\frac{2+3+4}{24}=\frac{9}{24}\]
    \[\therefore \](A + B + C)'s 1 days? work
    \[=\frac{9}{24\times 2}=\frac{9}{48}\]                           ?(iv)
    On, subtracting Eq. (iii) from Eq. (iv), we get
    B?s 1 day's work \[=\frac{9}{48}-\frac{1}{6}=\frac{9-8}{48}=\frac{1}{48}\]
    \[\therefore \] B can complete the work in 48 days.


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