A) 14
B) 28
C) 8
D) 6
Correct Answer: C
Solution :
The area of the \[\Delta ABC\]whose points \[A\equiv ({{x}_{1}}{{y}_{1}}),\]\[B\equiv ({{x}_{2}},{{y}_{2}})\] and \[C\equiv \,\,({{x}_{3}},{{y}_{3}})\]are given by area of \[\Delta ABC\] \[=\left[ \frac{1}{2}[{{x}_{1}}({{y}_{2}}-{{y}_{3}})+{{x}_{2}}({{y}_{3}}-{{y}_{1}})+{{x}_{3}}({{y}_{1}}-{{y}_{2}})] \right]\] Here, \[{{x}_{1}}=3,\]\[{{y}_{1}}=0,\]\[{{x}_{2}}=7,\]\[{{y}_{2}}=0,\] \[{{x}_{3}}=8,\]\[{{y}_{3}}=4\] \[=\frac{1}{2}[3\,\,(0-4)+7\,\,(4-0)+8\,\,(0-0)]\] \[=\frac{1}{2}[-12+28-0]=\frac{1}{2}(16)=8\]
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