A) 1 : 4
B) 2 : 3
C) 3 : 5
D) 5 : 6
Correct Answer: C
Solution :
Let the present ages of brothers be x and 2x yr, Then, 5 yr ago \[\frac{x-5}{2x-5}=\frac{1}{3}\Rightarrow 3x-15=2x-5\] \[\Rightarrow \] \[x=15-5=10\] \[\therefore \] Age of elder brother \[=10\times 2=20\] \[\therefore \] Required ratio \[=\frac{10+5}{20+5}=\frac{15}{25}=3:5\]You need to login to perform this action.
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