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SSC Sample Paper Mock Test-7 SSC CGL Tear-II Paper-1

  • question_answer
    If \[ax+by+p=0\] and \[ax-cy-q=0,\] then the value of x is

    A)  \[-\frac{p+q}{b+c}\]

    B)  \[\frac{bq-pc}{a\,\,(b+c)}\]

    C)  \[\frac{bq+pc}{a\,\,(b+c)}\]

    D)  \[\frac{a\,\,(b+c)}{bq+pc}\]

    Correct Answer: B

    Solution :

    By cross-multiplication method, \[\frac{x}{-\,\,bq+pc}=\frac{y}{ap+aq}=\frac{1}{-\,\,ac-ab}\] \[\Rightarrow \]   \[x=\frac{-bq+pc}{-\,\,ac-ab}\] \[x=\frac{bq-pc}{a\,\,(b+c)}\]


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