A) 4.05 cm
B) 4 cm
C) 3.5 cm
D) 3 cm
Correct Answer: D
Solution :
\[\sqrt{19}-\sqrt{17}=\frac{(\sqrt{19}-\sqrt{17})\times (\sqrt{19}\times \sqrt{17})}{\sqrt{19}+\sqrt{17}}\] |
\[\frac{19-17}{\sqrt{19}+\sqrt{17}}=\frac{2}{\sqrt{19}+\sqrt{17}}\] |
Similarly, \[\sqrt{13}-\sqrt{11}=\frac{2}{\sqrt{13}+\sqrt{11}}\] |
\[\sqrt{7}-\sqrt{5}=\frac{2}{\sqrt{7}+\sqrt{5}}\] |
\[\sqrt{5}-\sqrt{3}=\frac{2}{\sqrt{5}+\sqrt{3}}\] |
Clearly, \[\sqrt{5}-\sqrt{3}\]is the greatest. |
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