A) 7
B) 11
C) 13
D) None of these
Correct Answer: C
Solution :
Suppose the numbers are x and \[(x+2)\] Then from question itself \[x\times (x+2)=28899\] \[\Rightarrow \] \[{{x}^{2}}+2x=28899\] \[\Rightarrow \] \[{{x}^{2}}+2x-2899=0\] \[\Rightarrow \] \[{{x}^{2}}+171x-169x-28899=0\] \[\Rightarrow \] \[x\,\,(x+171)-169\,\,(x+171)=0\] \[\Rightarrow \] \[(x-169)(x+171)=0\] \[\Rightarrow \] \[x-169=0\] x = 169 Positive value So, square root of small numbers = 13You need to login to perform this action.
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