A) 840
B) 841
C) 820
D) 814
Correct Answer: D
Solution :
Length of the floor \[=15\,\,\text{m}\,\,17\,\,\text{cm}=1517\,\,\text{cm}\] |
Breadth of the floor \[=9\,\,\text{m}\,\,2\,\,\text{m}=902\,\,\text{cm}\] |
Area of the floor \[=1517\times 902\,\,\text{c}{{\text{m}}^{2}}\] |
The number of square tiles will be least, when the size of each tile is maximum. |
\[\therefore \]Size of each tile = HCF of 1517 and 902 = 41 |
\[\therefore \]Required number of tiles \[=\frac{1517\times 902}{41\times 41}=814\] |
You need to login to perform this action.
You will be redirected in
3 sec