A) 6
B) 3
C) \[\frac{3}{2}\]
D) \[\frac{3}{4}\]
Correct Answer: C
Solution :
Given a = 3 cm, A = 4 cm, 0 = 5 cm |
\[s=\frac{a+b+c}{2}=\frac{3+4+5}{2}\] |
\[=\frac{12}{2}=6\] |
From Hero's formula |
Area of \[\Delta ABC=\sqrt{s\,\,(s-a)(s-b)(s-c)}\] |
\[=\sqrt{6\,\,(6-3)(6-4)(6-5)}=6\,\,c{{m}^{2}}\] |
Area of \[\Delta PQR=\frac{1}{4}\times \Delta ABC\] |
\[=\frac{1}{4}\times 6=\frac{3}{2}\,\,\text{c}{{\text{m}}^{2}}\] |
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