A) \[{{p}^{2}}+3pq\]
B) \[{{p}^{2}}-3pq\]
C) \[{{p}^{3}}+3pq\]
D) \[{{p}^{3}}-3qp\]
Correct Answer: D
Solution :
We have \[\alpha +\beta =p\]and \[\alpha \beta =q\] \[({{\alpha }^{3}}+{{\beta }^{3}})={{(\alpha +\beta )}^{3}}-3\alpha \beta \,\,(\alpha +\beta )=({{p}^{3}}-3qp)\]You need to login to perform this action.
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