A) 7, 1
B) 2, 5
C) \[-\,\,6,3\]
D) \[-\,\,7,1\]
Correct Answer: A
Solution :
As obtained by A, we have \[\alpha +\beta =8\] and \[\alpha \beta =12\] |
\[\therefore \]The equation is \[{{x}^{2}}-8x+12=0\] |
As obtained by JS, we have \[\alpha +\beta =-\,\,8\] and \[\alpha \beta =7\] |
\[\therefore \]The equation is \[{{x}^{2}}+8x+7=0\] |
Hence, the correct equation is \[{{x}^{2}}-8x+7=0\] |
Now, \[{{x}^{2}}-8x+7=0\] \[\Rightarrow \]\[{{x}^{2}}-7x-x+7=0\] |
\[\Rightarrow \]\[x\,\,(x-7)-(x-7)=0\] \[\Rightarrow \]\[(x-7)(x-1)=0\] |
\[\Rightarrow \]\[x=7\] or \[x=1\] |
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