SSC Sample Paper Mock Test-8 SSC CGL Tear-II Paper-1

  • question_answer
    A path of uniform width surrounds a circular park. The difference of internal and external circumferences of this circular path is 132 m. Its width is \[\left( \text{Take}\,\,\pi =\frac{22}{7} \right)\]

    A) 22 m

    B)  20 m    

    C)  21 m   

    D)  24 m

    Correct Answer: C

    Solution :

    Let the internal radius of the park be r and the external radius (with the path) be R. The difference between the internal and external circumferences is 132 m. \[\therefore \]      \[2\pi R-2\pi r=132\] \[\Rightarrow \]   \[2\pi \,\,(R-r)=132\] \[\Rightarrow \]   \[R-r=\frac{132}{2\pi }=\frac{132\times 7}{2\times 22}=21\] Hence,  the width of path = 21 m


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