SSC Sample Paper Mock Test-8 SSC CGL Tear-II Paper-1

  • question_answer
    If\[47.2506=4\,\,A+\frac{7}{B}+2C+\frac{5}{D}+6E,\] then the value of 5A +3B +6C +D + 3E is

    A) 53.6003

    B)  53.603

    C)  153.6003

    D)  213.0003

    Correct Answer: C

    Solution :

    \[4A+\frac{7}{B}+2C+\frac{5}{D}+6E=47.2506\]
    \[4A=40\Rightarrow A=10\]
    \[\frac{7}{B}=7\Rightarrow 7B=7\Rightarrow B=1\] \[2C=\frac{2}{10}\Rightarrow C=0.1\]
    \[\frac{5}{D}=\frac{5}{100}\Rightarrow D=100\]
    \[6E=\frac{6}{10000}\Rightarrow E=0.0001\]
    \[=5A+3B+6C+D+3E\]
    \[=5\times 10+3\times 1+6\times 0.1+100+3\times 0.0001\]
    \[=50+3+0.6+100+0.0003=153.6003\]


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