A) 4
B) 5
C) 10
D) 6
Correct Answer: B
Solution :
Let the number be x. According to the question, \[3\times {{x}^{2}}-4\times x=x+50\] \[\Rightarrow \] \[3{{x}^{2}}-5x-50=0\] \[\Rightarrow \] \[3{{x}^{2}}-15x+10x-50=0\] \[\Rightarrow \] \[3x\,\,(x-5)+10\,\,(x-5)=0\] \[\Rightarrow \] \[(x-5)(3x+10)=0\] \[\Rightarrow \] \[x=5\] or \[\frac{-10}{3}\] But the number is natural. \[\therefore \]\[\ne -\frac{10}{3}.\]Hence, the required number = 5
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