A) 4, 3
B) \[-\,\,4,3\]
C) \[4,\,\,-3\]
D) \[-\,\,4,-\,\,3\]
Correct Answer: C
Solution :
\[\sqrt{25-{{x}^{2}}}=(x-1)\] On squaring both sides, we get \[(25-{{x}^{2}})={{(x-1)}^{2}}\] \[\Rightarrow \] \[(25-{{x}^{2}})=({{x}^{2}}-2x+1)\] \[\Rightarrow \] \[2{{x}^{2}}-2x-24=0\] \[\Rightarrow \] \[{{x}^{2}}-x-12=0\] \[\Rightarrow \] \[{{x}^{2}}-4x+3x-12=0\] \[\Rightarrow \] \[x\,\,(x-4)+3\,\,(x-4)=0\] \[\Rightarrow \] \[(x-4)(x+3)=0\]\[\Rightarrow \]\[x=4\] or \[x=-\,\,3\]
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