question_answer

The median BD of the AABC meets AC at D. If \[BD=\frac{1}{2}AC,\] then which one of the following is correct?

A)  \[\angle ACB=1\]right angle       

B)  \[\angle BAC=1\]right angle

C)  \[\angle ABC=1\]right angle  

D)  None of these

Correct Answer: C

Solution :

Here, we see that                           \[CD=BD=DA\] This is possible only when ABC is right angled triangle