SSC Sample Paper Mock Test-8 SSC CGL Tear-II Paper-1

  • question_answer
    The value of \[\frac{\cos 15{}^\circ -\sin 15{}^\circ }{\cos 15{}^\circ +\sin 15{}^\circ }\]is equal to

    A)  \[\frac{1}{\sqrt{3}}\]    

    B)  \[\sqrt{3}\]

    C)  \[\frac{1}{2}\]

    D)  1

    Correct Answer: A

    Solution :

    \[\frac{\cos 15{}^\circ -\sin 15{}^\circ }{\cos 15{}^\circ +\sin 15{}^\circ }\] Divide numerator and denominator by \[\cos 15{}^\circ \] \[=\frac{1-\tan 15{}^\circ }{1+\tan 15{}^\circ }=\frac{\tan 45{}^\circ -\tan 15{}^\circ }{1+\tan 45{}^\circ \tan 15{}^\circ }=\tan \,\,(45{}^\circ -15{}^\circ )\] \[=\tan 30{}^\circ =\frac{1}{\sqrt{3}}\]


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